项目二 顺序结构程序设计
12编写程序
(2)
void main()
{

float r,h;
double v;
scanf("%f,%f",&r,&h);
v=(3.14*r*r)*h/2;
v=v*100;
v=v+0.5
v=(int)v;
v=v/100;
printf("v=%f\n",v);
}
(3)
void main()
{
double c,f;
scanf("%lf",&c);
f=5/9*c+32;
printf("f=%f\n",f);
}

(4)
{
int m;
printf("input m:");
scanf("%d",&m);
a=m/100;
b=m%100/10;
c=m%10;
m=c*100+b*10+a;
printf("%d\n",m);
}

(5)
void main()
{
int a,b;
scanf("%d,%d",&a,&b);
printf("a+b=%d\n",a+b);
printf("a-b=%d\n",a-b);
printf("a*b=%d\n",a*b);
printf("a/b=%d\n",a/b);
printf("a/b=%f\n",(float)a/b);
printf("a%%b=%d\n",a%b);
}

(6)
#include"stdio.h"
void main()
{
char ch,ch1,ch2;
ch=getchar();
ch1=ch-1;
ch2=ch+1;
printf("%c,%c\n",ch1,ch2);
}

(7)
void main()
{
int m;
scanf("%d",&m);
a=m/1000;
b=m/100%10;
c=m%100/10;
d=m%10;
a=(a+5)%10;
b=(b+5)%10;
c=(c+5)%10;
d=(d+5)%10;
m=d*1000+c*100+b*10+a;
printf("%d\n",m);
}
(8)
#include"math.h"
void main()
{
double a,n,p,y;
scanf("%lf,%lf,%lf",&a,&n,&p);
y=a*pow((1+p),n)-a;
printf("年利率为%f\n",y);
}

项目三 选择结构程序设计

6编写程序
(2)
void main()
{
int m;
printf("input m:");
scanf("%d",&m);
if(m%5==0&&m%7==0) printf("yes\n");
else printf("no\n");
}

(3)
void main()
{
int x,y,z;
printf("input x,y,z:");
scanf("%d,%d,%d",&x,&y,&z);
if(x*x+y*y+z*z>1000)
printf("%d\n",x*x+y*y+z*z);
else
printf("%d\n",x+y+z);
}

(4)
#include"stdio.h"
void main()
{
char ch1,ch2;
int m,t;
scanf("%c,%c",&ch1,&ch2);
if(ch1<ch2){t=ch1;ch1=ch2;ch2=t;}
m=ch1-ch2
if(m%2==0) printf("%c\n",ch1+1);
else printf("%c\n",ch2-1);
}

(5)
void main()
{
int m,gz;
scanf("%d",&m);
if(m>160)
gz=160*5+(m-160)*15;
else
gz=m*5;
printf("gz=%d\n",gz);
}


(6)
void main()
{
float gz,jz1,jz2,jz3,jz4;
float x;
scanf("%f",&x);
jz1=1000*0.1;
jz2=jz1+2000*0.15;
jz3=jz2+5000*0.20;
jz4=jz3+10000*0.25;
if(x<=2000)
jz=jz1+(x-1000)*0.1;
else if(x<=5000)
jz=jz2+(x-2000)*0.15;
else if(x<=10000)
jz=jz3+(x-5000)*.0.20;
else 
jz=jz4+(x-10000)*0.25;
gz=500+jz;
printf("gz=%f\n",gz);
    
}

(7)
void main()
{
int m,n=0;
printf("input m:");
scanf("%d",&m);
if(m%3==0) n=n+1;
if(m%5==0) n=n+1;
if(m%7==0) n=n+1;

printf("n=%d\n",n);
}

(8)
void main()
{
int a,b;
char ch;
scanf("%d,%d",&a,&b);
scanf("%c",&ch);
switch(ch)
{
case '+':
printf("a+b=%d\n",a+b);
case '-':
printf("a-b=%d\n",a-b);
case '*':
printf("a*b=%d\n",a*b);
case '/':
printf("a/b=%d\n",a/b);
}
}

(9)
void main()
{
long n;
int m=0,a,b,c,d,e;
scanf("%ld",&n);
if(n>9999) 
{
m=5;
a=n/10000;
b=n%10000/1000;
c=n/100%10;
d=n%100/10;
e=n%10;
printf("%d是一个%d位数字\n",n,m);
printf("%d位数字分别是:%d %d %d %d %d\n",a,b,c,d,e);
}
else if(n>999)
     {m=4;
      a=n/1000;
      b=n%1000/100;
      c=n%100/10;
      d=n%10;
      printf("%d是一个%d位数字\n",n,m);
      printf("%d位数字分别是:%d %d %d %d\n",m,a,b,c,d);   
      }
      else if(n>99)
           {m=3;
            a=n/100;
            b=n%100/10;
            c=n%10;
            printf("%d是一个%d位数字\n",n,m);
            printf("%d位数字分别是:%d %d %d\n",m,a,b,c);
            }
           else if(n>9)
            {m=2;
             a=n/10;
             b=n%10;
             printf("%d是一个%d位数字\n",n,m);
             printf("%d位数字分别是:%d %d\n",m,a,b);
             }
                else
                {m=1;
                 printf("%d是一个%d位数字\n",n,m);
                 printf("%d位数字分别是:%d\n",m,n);
                 }
}

(10)

这个题有问题，数字不是奇数就是偶数。

(11)

void main()
{
double x,y;
if(x>=3&&x<8)
{if(x==(int)x)
y=10+(int)(x-3)*1.6;
else 
y=10+(int)(x-2)*1.6;
}
if(x>=8)
{
if(x==int(x))
y=18+(int)(x-8)*2;
else
y=18+(int)(x-7)*2;
}
}

}

项目四 循环结构程序设计

7编写程序
(2)
void main()
{
int i=0,s=0;
while(s<1000)
{i++;
s=s+i;
}
printf("i=%d,s=%d\n",i,s);
}

(3)
void main()
{
int i=0,s=0;
while(s<1000)
{
i+=2;
s=s+i;
}
printf("i=%d,s=%d\n",i,s);
}

(4)
void main()
{
int i;
long s=0;
for(i=1;i<=20;i++)
s=s+i*(i+1)*(i+2);
printf("s=%ld\n",s);
}

(5)
void main()
{
int i,n=1;
double s=0;
for(i=1;i<20;i++)
{
n=n*i;
s=s+1.0/n;
}
printf("s=%f\n",s);
}

(6)
void main()
{
int i;
for(i=100;i<999;i++)
if(i%3==2&&i%5==3&&i%7==4) printf("%d  ",i);
printf("\n");
}

(7)

void main()
{
int i;
for(i=4;i<=99;i++)
if((i%10==i)&&(i*i%10==i)) printf("%d  ",i);
else if((i%10!=i)&&(i*i%100==i)) printf("%d  ",i);
}

(8)
void main()
{
int i,a,b,c;
for(i=3;i<=999;i+=3)
{
a=i/100;
b=i%100/10;
c=i%10;
if(a==5||b==5||c==5) printf("%d  ",i);
}
printf("\n");
}

(9)
void main()
{
int a,n,i=1;
long sn=0,tn=0;
printf("a,n=:");
scanf("%d,%d",&a,&n);
while(i<=n)
{
tn=tn+a;
sn=sn+tn
a=a*10;
++i;
}

printf("a+aa+aaa+...=%ld\n",sn);
}

(10)
void main()
{
 float sn=200,hn=sn/4;
int n;
for(n=2;n<=10;n++)
{
sn=sn+2*hn;
hn=hn/4;
}

printf("第10次落地时共经过%f m.\n",sn);
printf("第10次反弹%f m.\n",hn);
}

    
(11)
void  main()   
   {   
         int    hen,rabbit,h,f;   
         printf("Input    head    and    foot:\n");   
         scanf("%d%d",&h,&f);   
         rabbit=(f-h-h)/2;   
         hen=h-rabbit;   
         printf("%d hens and %d rabbits\n",hen,rabbit);   
           
   } 
(12)
/* 百钱百鸡问题：100元买100只鸡，其中公鸡5元1只，母鸡3元1只，
      小鸡1元3只，要求每种鸡至少有1只，要求编写程序统计并输出所有购买方案。 */

#include "Stdio.h"

void main()
{
 int cock,hen,chick,cond,num;
 for(cock=1;cock<=20;cock++)
 {
   for(hen=1;hen<33;hen++)
     {
      chick=100-cock-hen;
      cond=chick%3;
      num=5*cock+3*hen+chick/3;
      if(cond==0&&num==100)
      {printf("cock=%d zhi\then=%d zhi\tchick=%d zhi\ttotal=%d zhi\n",
      cock,hen,chick,cock+hen+chick);
      printf("cock*5=%d yuan\then*3=%d yuan\tchick/3=%d yuan total=%d yuan\n",
      cock*5,hen*3,chick/3,cock*5+hen*3+chick/3);
      printf("\n\n");}}}
  
}

(13)
void main()
{

int m,n;
for(m=1;m<5;m++)
for(n=1;n<9;n++)
if(m*20+n*10==100) printf("%d  %d\n",m,n);
}

(14)
void main() 
{int i,sum=1; 
for(i=1;i<10;i++) 
sum=(sum+1)*2; 
printf("%d",sum); 
} 

(15)
void main()
{
int m=1;
while(1)
{
if(m%2==1&&m%3==2&&m%5==4&&m%6==5&&m%7==0)
 {
  printf("%d\n",m);
  break;
 }
 m++;
}
}

(16)
void main()
{
int f1=1;f2=1;f3;
for(i=3;i<=12;i++)
{
f3=f1+f2;
f1=f2;
f2=f3;
}
printf("f3=%d\n",f3);
}

(17)
void main()
{
int m,n=0;
for(m=2000;m<=2500;m++)
{
if(n%5==10) printf("\n");
if((m%400==0)||(m%4==0&&m%100!=0)) { printf("%d  ",m); n++; }
}

}

(18)第一个图案
void main() 
{ 
int a, b, n ; 
for(a=1;a<=9;a++) 
{ 
for(b=1;b<=a;b++)  printf("%d*%d=%2d ",b,a,a*b); 
printf("\n"); 
} 
} 

第二个图案

void main()
{int i,j,k;
for(i=1;i<=9;i++)
{for(j=1;j<4*i;j++) printf(" ");
 for(k=i;k<=9;k++) printf("%2d  ",k*i);
 printf("\n");
}
}
/*注意：printf("%2d  ",k*i);这条语句里的%2d后面有两个空格*/

(19)
#include"math.h"
void main()
{

float x,x0,f,f1;
x=1.5;
do
{
x0=x;
f=((2*x0-4)*x0+3)*x0-6;
f1=(6*x0-8)*x0+3;
x=x0-f/f1;
}
while(fabs(x-x0)>=1e-6);
printf("the root of equation is %5.2f\n",x);
}